Articles
Register
Sign In
Search
Lauremaes
@Lauremaes
April 2019
1
97
Report
Développer et réduire A.
Factoriser A.
A = (x-5)^2-(2x-7)(x-5).
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
senmusa
Verified answer
On développe:
A= x² + 25 - 10x - 2x² + 10x + 7x - 35
et on réduit:
A = - x² + 7x - 10
Factorisation: on va mettre (x-5) en évidence:
A= (x-5) (x-5 - 2x + 7)
= (x-5)(-x+2)
1 votes
Thanks 2
More Questions From This User
See All
lauremaes
February 2021 | 0 Respostas
Responda
lauremaes
February 2021 | 0 Respostas
Responda
lauremaes
January 2021 | 0 Respostas
Responda
lauremaes
January 2021 | 0 Respostas
Responda
Lauremaes
May 2019 | 0 Respostas
Responda
×
Report "Développer et réduire A. Factoriser A. A = (x-5)^2-(2x-7)(x-5).... Pergunta de ideia de Lauremaes"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
On développe:A= x² + 25 - 10x - 2x² + 10x + 7x - 35
et on réduit:
A = - x² + 7x - 10
Factorisation: on va mettre (x-5) en évidence:
A= (x-5) (x-5 - 2x + 7)
= (x-5)(-x+2)