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kiceki
@kiceki
June 2021
1
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developper et réduire
(x+9)(3-2x)
(3y+5)(10+y)
(z-2)(3-z)
5(3g+1)(g-2)
(2x-1)(x²+3)
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yayane97
3x-2x*+27-18x. Soit 2x*-15x+27 *=au carré 30y+3y*+50+5y. Soit 3x*+35y+50 3z-z*-6+2z. Soit -z*+5z-6 5(3g*-6g+g-2)=15g*-30g+5g-10. Soit 15g*-25g-10 2x^3+6x-x*-3. Soit 2x^3-x*+6x-3
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