Articles
Register
Sign In
Search
moi69
@moi69
June 2021
2
62
Report
développer puis reduire svp 100000000000000fois ...... aidez-moi
a-(x+4)(x+2) b-(x+2)(0,5+x)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Cabé
A = (x+4)(x+2)
A = x
²
+ 4x + 2x + 8
A = x
²
+ 6x + 8
B = (x+2)(0,5+x)
B = 0,5x + 1 + x
²
+ 2x
B = x
²
+ 2,5x + 1
0 votes
Thanks 1
MrEagle
a) ( x + 4 ) ( x + 2 )
= x* x + x * 2 + 4 * x + 4 * 2
= x^2 + 2x + 4x + 8
= x^2 + 6x + 8
b) ( x + 2 ) ( 0,5 + x )
= x* 0,5 + x * x + 2 * 0,5 + 2 * x
= 0,5x + x^2 + 1 + 2x
= x^2 + 2,5x + 1
0 votes
Thanks 1
More Questions From This User
See All
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
moi69
June 2021 | 0 Respostas
Responda
Moi69
April 2019 | 0 Respostas
Responda
×
Report "développer puis reduire svp 100000000000000fois ...... aidez-moia-(x+4)(x+2) b-(x+2)(0,5+x).... Pergunta de ideia de moi69"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2025 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
A = x² + 4x + 2x + 8
A = x² + 6x + 8
B = (x+2)(0,5+x)
B = 0,5x + 1 + x² + 2x
B = x² + 2,5x + 1
= x* x + x * 2 + 4 * x + 4 * 2
= x^2 + 2x + 4x + 8
= x^2 + 6x + 8
b) ( x + 2 ) ( 0,5 + x )
= x* 0,5 + x * x + 2 * 0,5 + 2 * x
= 0,5x + x^2 + 1 + 2x
= x^2 + 2,5x + 1