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naruto0007
@naruto0007
January 2021
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Bonsoir j'aurai besoin d'aide pour mon DM de Mathématiques (Exercice 3)
Aller sur se lien ; http://www.mathematiques-web.fr/wp-content/uploads/2013/09/devoir-maison-maths-troisieme-4.pdf
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CaVa
Bonsoir, voilà la réponse
1). J'appelle Aire l'aire du rectangle BCEF
Aire = BC * EC
= (2x – 3) * (2x- 3 – (x+1))
= (2x – 3) * (x – 4 )
= 2x² – 8x – 3x + 12
= 2x² – 11x +12
A = (2x – 3)² – (2x-3)(x+1)
A = 2x² - 12x + 9 - ( 2x² + 2x -3x – 3)
A = 4x² - 12x + 9 - 2x² - 2x + 3x + 3
A = 2x² – 11x +12
Donc Aire = A
Donc l'aire du rectangle BCEF s'exprime par la formule A = (2x – 3)² – (2x-3)(x+1)
2).
A = (2x – 3)² – (2x-3)(x+1)
A = 2x² - 12x + 9 - ( 2x² + 2x -3x – 3)
A = 4x² - 12x + 9 - 2x² - 2x + 3x + 3
A = 2x² – 11x +12
3). A = 2x² – 11x + 12
A = (2x – 3) (x – 4 )
4). Pour x = 5
A= (2*5 – 3)(5 – 4)
A = (10 – 3) x 1
A = 7
Voilà, si tu as des questions n'hésite pas ou si tu comprends pas.
Bonne fête!
2 votes
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1). J'appelle Aire l'aire du rectangle BCEF
Aire = BC * EC
= (2x – 3) * (2x- 3 – (x+1))
= (2x – 3) * (x – 4 )
= 2x² – 8x – 3x + 12
= 2x² – 11x +12
A = (2x – 3)² – (2x-3)(x+1)
A = 2x² - 12x + 9 - ( 2x² + 2x -3x – 3)
A = 4x² - 12x + 9 - 2x² - 2x + 3x + 3
A = 2x² – 11x +12
Donc Aire = A
Donc l'aire du rectangle BCEF s'exprime par la formule A = (2x – 3)² – (2x-3)(x+1)
2).
A = (2x – 3)² – (2x-3)(x+1)
A = 2x² - 12x + 9 - ( 2x² + 2x -3x – 3)
A = 4x² - 12x + 9 - 2x² - 2x + 3x + 3
A = 2x² – 11x +12
3). A = 2x² – 11x + 12
A = (2x – 3) (x – 4 )
4). Pour x = 5
A= (2*5 – 3)(5 – 4)
A = (10 – 3) x 1
A = 7
Voilà, si tu as des questions n'hésite pas ou si tu comprends pas.
Bonne fête!