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elohliima
@elohliima
March 2022
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Dividir o número 160 em três partes diretamente proporcionais aos números 2, 3 e 5. ' me ajudem pfpfpf '
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poty
Verified answer
A+B+C= 160
2+3+5 = 10
A + B + C
=
160
= 16
2 + 3 + 5 10
Partes Proporcionais:
A
= 16 --> A = 16 .2 = 32
2
B
= 16 --> B = 16 .3 = 48
3
C
= 16 --> C = 16 .5 = 80
5
32 + 48 + 80 = 160
4 votes
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Lista de comentários
Verified answer
A+B+C= 1602+3+5 = 10
A + B + C = 160 = 16
2 + 3 + 5 10
Partes Proporcionais:
A = 16 --> A = 16 .2 = 32
2
B = 16 --> B = 16 .3 = 48
3
C = 16 --> C = 16 .5 = 80
5
32 + 48 + 80 = 160