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Agathe33
@Agathe33
May 2019
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E: (x-1)(5x+7)-(5x+7)(4x-9)=0.
F:(-9x+2)(8x+5)=(2x+5)(-x+3)
Merci d’avance!
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MonsieurFirdown
Verified answer
Bonjour
♧a.
(x-1)(5x+7)-(5x+7)(4x-9) = 0
(5x+7)[(x-1)-(4x-9)] = 0
(5x+7)(x-1-4x+9) = 0
(5x+7)(-3x+8) = 0
♡ Un Produit de facteur est nul si et seulement si au moins l'un des facteurs est nul on a donc :
5x+7 = 0 ou -3x+8 = 0
5x = - 7 ou -3x = - 8
x = - 7/5 ou x = 8/3
S={-7/5 ; 8/3}
♧ À toi de faire l'autre. ...
Voilà ^^
1 votes
Thanks 2
MonsieurFirdown
^^
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Verified answer
Bonjour♧a.
(x-1)(5x+7)-(5x+7)(4x-9) = 0
(5x+7)[(x-1)-(4x-9)] = 0
(5x+7)(x-1-4x+9) = 0
(5x+7)(-3x+8) = 0
♡ Un Produit de facteur est nul si et seulement si au moins l'un des facteurs est nul on a donc :
5x+7 = 0 ou -3x+8 = 0
5x = - 7 ou -3x = - 8
x = - 7/5 ou x = 8/3
S={-7/5 ; 8/3}
♧ À toi de faire l'autre. ...
Voilà ^^