en commpletant les pointillies de l'expression:4...4...4...4par des signes operatoires(+,-,x,:)Marie a reussie a obtenir tous les nombres entiers de 0 a 9.Comment a-t-elle procedé?
4...4...4...4
4-4+4-4 = 0 + 0 = 0
4-4+4:4 = 0 + 1 = 1
4:4+4:4 = 1 + 1 = 2
(4+4+4):4 = 12:4 = 3
(4-4)x4+4 = 0x4+4 = 0 + 4 = 4
(4x4+4):4 = (16+4):4 = 20:4 = 5
(4+4):4+4 = 8:4 + 4 = 2 + 4 = 6
4+4-4:4 = 8-1 = 7
4x4-4-4 = 16-8=8
4+4+4:4 = 8+1 = 9
En espérant t'avoir aidé.
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4...4...4...4
4-4+4-4 = 0 + 0 = 0
4-4+4:4 = 0 + 1 = 1
4:4+4:4 = 1 + 1 = 2
(4+4+4):4 = 12:4 = 3
(4-4)x4+4 = 0x4+4 = 0 + 4 = 4
(4x4+4):4 = (16+4):4 = 20:4 = 5
(4+4):4+4 = 8:4 + 4 = 2 + 4 = 6
4+4-4:4 = 8-1 = 7
4x4-4-4 = 16-8=8
4+4+4:4 = 8+1 = 9
En espérant t'avoir aidé.