4+x(x-4)=x
4 + x² - 4x = x
x² - 4x - x + 4 = 0
x² - 5x + 4 = 0
A= 1
B= - 5
C= 4
∆= b² - 4ac
∆= ( - 5)² - 4 • 1 • 4
∆= 25 - 16
∆= 9
x= - b ± √∆ /2a
x= - ( - 5) ± √9 /2 • 1
x= 5 ± 3/2
x'= 5 + 3/2 = 8/2 = 4
x''= 5 - 3/2 = 2/2 = 1
S= ( 1 , 4)
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4+x²-4x-x=0
x² -5x + 4 = 0
Δ=25-4(1)(4) = 25 - 16 = 9
x1 = (5 + 3)/2 = 4
x2 = (5 - 3)/2 = 1
Espero ter ajudado
4+x(x-4)=x
4 + x² - 4x = x
x² - 4x - x + 4 = 0
x² - 5x + 4 = 0
A= 1
B= - 5
C= 4
∆= b² - 4ac
∆= ( - 5)² - 4 • 1 • 4
∆= 25 - 16
∆= 9
x= - b ± √∆ /2a
x= - ( - 5) ± √9 /2 • 1
x= 5 ± 3/2
x'= 5 + 3/2 = 8/2 = 4
x''= 5 - 3/2 = 2/2 = 1
S= ( 1 , 4)