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ibtissben098
@ibtissben098
January 2021
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Bonjour pourriez-vous m'aider svp à résoudre ces équations ?
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nini999
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Bonsoir :
1)
3x - 12 = 0
3x = 12
x = 12/3
x = 4
2)
7x - 8 = 2x+4
7x-2x = 4+8
5x = 12
x = 12/5
3)
(2x-3)(-4x+7) = 0
Soit : 2x-3 = 0 ou -4x+7 = 0
: 2x = 3 ou -4x = -7
: x = 3/2 ou 4x = 7
Donc: x = 3/2 ou x = 7/4
4)
(5x-6)² = 36
(5x-6)² - 36 = 0
(5x-6)² - 6² = 0
(5x-6)² - 6² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
[(5x-6)-6][(5x-6)+6] = 0
(5x-6-6)(5x-6+6) = 0
(5x-12)(5x-0) = 0
(5x-12)(5x) = 0
Soit : 5x-12 = 0 ou 5x = 0
: 5x = 12 ou x = 0/5
Donc: x = 12/5 ou x = 0
C'est ton tour fait 4
J’espère t'avoir t'aider
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Verified answer
Bonsoir :1)
3x - 12 = 0
3x = 12
x = 12/3
x = 4
2)
7x - 8 = 2x+4
7x-2x = 4+8
5x = 12
x = 12/5
3)
(2x-3)(-4x+7) = 0
Soit : 2x-3 = 0 ou -4x+7 = 0
: 2x = 3 ou -4x = -7
: x = 3/2 ou 4x = 7
Donc: x = 3/2 ou x = 7/4
4)
(5x-6)² = 36
(5x-6)² - 36 = 0
(5x-6)² - 6² = 0
(5x-6)² - 6² il prend la forme de a²-b² = (a-b)(a+b)
Alors :
[(5x-6)-6][(5x-6)+6] = 0
(5x-6-6)(5x-6+6) = 0
(5x-12)(5x-0) = 0
(5x-12)(5x) = 0
Soit : 5x-12 = 0 ou 5x = 0
: 5x = 12 ou x = 0/5
Donc: x = 12/5 ou x = 0
C'est ton tour fait 4
J’espère t'avoir t'aider