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Sasa49333
@Sasa49333
April 2019
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Est ce que quelque peut factoriser ceci :
(X+3)^2 - (5x-1)^2
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Thomas1106
(x+3)²-(5x-1)²
Cette expression est de la forme a²-b² avec a = x+3 et b = 5x-1
Rappel : a
²-b² = (a+b)(a-b)
(x+3)²-(5x-1)²
= (x+3+5x-1)[x+3-(5x-1)]
= (6x+2)(x+3-5x+1)
= (6x+2)(-4x+4)
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Thomas1106
De rien ! Bon week-end ;)
Commentaires (1)
(x+3)^2 - (5x-1)^2
= (x+3-5x+1)(x+3+5x-1)
= (-4x+4)(6x-2)
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Lista de comentários
Rappel : a²-b² = (a+b)(a-b)
(x+3)²-(5x-1)² = (x+3+5x-1)[x+3-(5x-1)]
= (6x+2)(x+3-5x+1)
= (6x+2)(-4x+4)
= (x+3-5x+1)(x+3+5x-1)
= (-4x+4)(6x-2)