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Vince931463
@Vince931463
April 2019
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Est-ce que quelqu'un peut m'aider ou me résoudre cette équation là SVP.
Merci
L'équation :
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Commentaires (2)
Bonjour,
(2y - 5)(4y - 1) + (2y + 3)(2y - 5) = 0
(2y - 5)[(4y - 1) + (2y + 3)] = 0
(2y - 5)(4y - 1 + 2y + 3) = 0
(2y - 5)(6y +2) = 0
2y - 5 = 0 ou 6y + 2 = 0
2y = 5 ou 6y = -2
y = 5/2 ou y = -2/6
y = 5/2 ou y = -1/3
S = {5/2 ; -1/3}
2 votes
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(2y - 5)(4y - 1) + (2y + 3)(2y - 5) = 0
(2y - 5)[(4y - 1) + (2y + 3)] = 0
(2y - 5)(4y - 1 + 2y + 3) = 0
(2y - 5)(6y +2) = 0
2y - 5 = 0 ou 6y + 2 = 0
2y = 5 ou 6y = -2
y = 5/2 ou y = -2/6
y = 5/2 ou y = -1/3
S = {5/2 ; -1/3}