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oliverfalconeroyy7zx
@oliverfalconeroyy7zx
January 2021
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Est-ce que quelqu’un pourrait m’aider pour cet exercice , merci
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nguyenso9
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Bonsoir,
Volume cône : pi x r² x h ÷ 3
a) r = 6 cm et h = 10 cm
V1 = pi x 6² x 10 ÷ 3
V1 ≈ 377 cm³
b) Le triangle est rectangle
D'apres le theoreme de Pythagore,
h² = 10² - 6²
h² = 64
h = √64 = 8
V2 = pi x 6² x 8 ÷ 3
V2 ≈ 302 cm³
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Verified answer
Bonsoir,Volume cône : pi x r² x h ÷ 3
a) r = 6 cm et h = 10 cm
V1 = pi x 6² x 10 ÷ 3
V1 ≈ 377 cm³
b) Le triangle est rectangle
D'apres le theoreme de Pythagore,
h² = 10² - 6²
h² = 64
h = √64 = 8
V2 = pi x 6² x 8 ÷ 3
V2 ≈ 302 cm³