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Emmacote
@Emmacote
April 2019
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Est ce que vous pourriez m'aider pour les exercices 3et4 svp?
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Incorrigible
Exo 3
1. Dans le triangle BAC:
tan(BÂC) = BC/BA
tan(40°)/1= BC/100
BC= 100xtan(40°) / 1 ≈83.9 m
2. Dans le triangle BAD:
tan(BÂD)= BD/BA
tan(55°) / 1 = BD/100
BD= 100x tan(40°) / 1 ≈ 142.8 m
3. 142.8 - 83.9 = 58.9 ≈ 59
Largeur de la rivière : environ 59m
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Incorrigible
attention ! j'ai échangé question 1 et 2 ! mais sinon ça change rien. pardon ^^
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Lista de comentários
1. Dans le triangle BAC:
tan(BÂC) = BC/BA
tan(40°)/1= BC/100
BC= 100xtan(40°) / 1 ≈83.9 m
2. Dans le triangle BAD:
tan(BÂD)= BD/BA
tan(55°) / 1 = BD/100
BD= 100x tan(40°) / 1 ≈ 142.8 m
3. 142.8 - 83.9 = 58.9 ≈ 59
Largeur de la rivière : environ 59m