Exercice 178 page 59 manuel seconde hatier édition 2019
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A (x) = ( 3 x - 5 ) ( 5 x + 1 )
A (x) = 15 x² + 3 x - 25 x - 5
A (x) = 15 x² - 22 x - 5
15 x² - 22 x - 5
α = 22/30 = 11/15
β = 15 ( 11/15)² - 22*11/15 - 5
β = 15 *121/225 - 242/15 - 5
β = 1815/225 - 242/15 - 5
β = 121/15 - 242/15 - 75/15 = - 196/15
A (x) = 15 ( x - 11 /15) ² - 196/15
A'x) = 5
15 x² - 22 x - 5 = - 5
15 x² - 22 x = - 5 + 5
15 x² - 22 x = 0
x = 0
A (x) = 0
( 3 x - 5 ) - 5 x + 1 ) = 0
x = 5/3 ou 1/5
A (x) = 15 x²
15 x² - 22 x - 5 = 15 x²
15 x² - 15 x² - 22 x - 5 = 0
- 22 x = 5
x = - 5/22
tu fais pareil pour le dernier