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Bonjour,

(3-2x)(5-x) - (3 - 2x)(7 - 4x)

=(3-2x) ( 5-x -7+4x)

= (3-2x) ( 3x -2)

(5 + x)(2x - 1) + (2x - 1)(3 + x)

(2x-1) ( 5+x +3+x)

= (2x-1) ( 2x +8)

2(3-x)(x + 2) - (x + 2)(4 + x)

= (x+2) ( 6-2x -4-x)

= (x+2) ( -3x +2)

(2x + 3)² + 5(2x + 3)

= (2x+3 ( 2x+3 +5)

=  (2x+3) ( 2x+8)

(2x - 3)(7 + 5x) - (2x - 3)

= (2x-3) ( 7+5x -1)

= (2x-3) ( 5x +6)

3(x + 1)(7 - 2x) + (7 - 2x)(2 + x) ​

=(7-2x) ( 3x+3 +2+x)

= (7-2x) ( 4x +5)

Réponse :

Explications étape par étape :

Bonjour

Factoriser

  (3-2x)(5-x) - (3 - 2x)(7 - 4x)
= (3-2x)[(5-x)-(7-4x)]
= (3 -2x)(5-x-7+4x)
=(3-2x)(3x-2)

 (5 + x)(2x - 1) + (2x - 1)(3 + x)
=(2x-1)(5+x+3+x)
=(2x-1)(2x+8)
=2(2x-1)(x+4)

 2(3-x)(x + 2) - (x + 2)(4 + x)
= (x+2)(2(3-x)-(4+x)]
=(x+2)(6-2x-4-x)
=(x+2)(-3x+2)

 (2x + 3)² + 5(2x + 3)
=(2x+3)(2x+3+5)
=(2x+3)(2x+8)
=2(2x+3)(x+4)

 (2x - 3)(7 + 5x) - (2x - 3)
=(2x-3)(7+5x-1)
=(2x-3)(5x+6)

 3(x + 1)(7 - 2x) + (7 - 2x)(2 + x)
=(7-2x)(3x+3+2+x)
=(7-2x)(4x+5)​