Explications étape par étape:
Bonjour
A=(x+3)(2x-1) + (x+3)(8x-3)
=(x+3) [(2x-1)+(8x-3)]
=(x+3)(2x-1+8x-3)
=(x+3)(10x-4)
[tex]b = ( - x + 5)(3x + 7) - (3x + 7)(2x {}^{2} + 1) \\ (3x + 7)( - x + 5 - 2x {}^{2} + 1) \\ (3x + 7)( - 2x {}^{2} - x + 6)[/tex]
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Explications étape par étape:
Bonjour
A=(x+3)(2x-1) + (x+3)(8x-3)
=(x+3) [(2x-1)+(8x-3)]
=(x+3)(2x-1+8x-3)
=(x+3)(10x-4)
[tex]b = ( - x + 5)(3x + 7) - (3x + 7)(2x {}^{2} + 1) \\ (3x + 7)( - x + 5 - 2x {}^{2} + 1) \\ (3x + 7)( - 2x {}^{2} - x + 6)[/tex]