Articles
Register
Sign In
Search
Jmsc
@Jmsc
April 2019
2
49
Report
Factoriser : 9,03x57+9,03x73-9,03x30=
53x16+53x84=
9a+27b-63c=
9a+3b=
developper : 4(2a+5b)+3(a+8b)+10(4a-b)=
4(x-3)+9(x+10)=
(2x-9)x5=
5(x+3)=
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
charlotte49
Factoriser:
9,03x57+9,03x73-9,03x30= 9,03( 57+73 - 30)
= 9,03 x 100
=903
53x16+53x84=53( 16+84)
= 53 x 100
= 5300
9a+27b-63c= 9( a + 3b -7c )
9a +3b = 3( 3a +b)
Développer :
4(2a+5b)+3(a+8b)+10(4a-b)=8a + 20b +3a + 24b +40a -10b
= 51a +34
4(x-3)+9(x+10)=4x -12 + 9x +90
= 13x +78
(2x-9)x5=10x² - 45x
5(x+3)= 5x + 15
J'espère que vous avez compris ..
1 votes
Thanks 1
telephone16
Factoriser:
9,03
X57+
9,03
X73-
9,03
X30
Facteur commun =
9,03
( 57+73 - 30)
9,03 X100 = 903
53X16+53X84
Facteur commun =
53
( 16+84)
53 X 100 = 5300
9a+27b-63c
Facteur commun =
9
( a + 3b -7c )
9a +3b = 3( 3a +b)
Développer :
4(2a+5b)+3(a+8b)+10(4a-b) tu appliques la distributivité
8a + 20b +3a + 24b +40a -10b
51a +34
4(x-3)+9(x+10)
4x -12 + 9x +90
13x +78
(2x-9)X 5
10x² - 45x
5
(x+3) = 5x + 15
0 votes
Thanks 0
More Questions From This User
See All
jmsc
June 2021 | 0 Respostas
Responda
Jmsc
August 2019 | 0 Respostas
Responda
Jmsc
April 2019 | 0 Respostas
Responda
Jmsc
April 2019 | 0 Respostas
Responda
Jmsc
April 2019 | 0 Respostas
Responda
Jmsc
April 2019 | 0 Respostas
Responda
×
Report "Factoriser : 9,03x57+9,03x73-9,03x30=53x16+53x84=9a+27b-63c=9a+3b=developper : 4(2a+5b)+3(a+8b)+10(4.... Pergunta de ideia de Jmsc"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
9,03x57+9,03x73-9,03x30= 9,03( 57+73 - 30)
= 9,03 x 100
=903
53x16+53x84=53( 16+84)
= 53 x 100
= 5300
9a+27b-63c= 9( a + 3b -7c )
9a +3b = 3( 3a +b)
Développer :
4(2a+5b)+3(a+8b)+10(4a-b)=8a + 20b +3a + 24b +40a -10b
= 51a +34
4(x-3)+9(x+10)=4x -12 + 9x +90
= 13x +78
(2x-9)x5=10x² - 45x
5(x+3)= 5x + 15
J'espère que vous avez compris ..
9,03X57+9,03X73-9,03X30
Facteur commun = 9,03( 57+73 - 30)
9,03 X100 = 903
53X16+53X84
Facteur commun = 53( 16+84)
53 X 100 = 5300
9a+27b-63c
Facteur commun = 9( a + 3b -7c )
9a +3b = 3( 3a +b)
Développer :
4(2a+5b)+3(a+8b)+10(4a-b) tu appliques la distributivité
8a + 20b +3a + 24b +40a -10b
51a +34
4(x-3)+9(x+10)
4x -12 + 9x +90
13x +78
(2x-9)X 5
10x² - 45x
5(x+3) = 5x + 15