Factoriser les expression suivant
a= (7x-3)(9-3x)-(4x-6)(7x-3)
b=(6+x)(4x+1)+4x+1(4x1)^2
c=(2y-5)(10y+4)-(2y-5)^2
developper et reduir : D= (5x-3)^2 - (2x-7)(5x-3)+35x-21
puis factoriser D
a= (7x-3)(9-3x)-(4x-6)(7x-3)
b=(6+x)(4x+1)+4x+1(4x1)^2
c=(2y-5)(10y+4)-(2y-5)^2
developper et reduir : D= (5x-3)^2 - (2x-7)(5x-3)+35x-21
puis factoriser D
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A=(7x-3) [9-3x-4x+6]
=(7x-3) [15-7x]
B= il a un faut voire il
C=(y-5) (10y+4)-(2y-5) ^ 2
=(2y-5) [10y+4-2y+5]
=(2y-5) [8y+9]
D=(5X-3)^2 - (2X-7) (5X-3) + 7(5x-3)
=(5x-3) [5x-3-2x+7+7]
=(5x-3) [3x+11] (c`est factorise)
D=25x^2 - 30x + 9 - (10x^2-6x-35x+21)+35x-21
=15x^2+46x-33
x=3/5 ou x=-11/3