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helloitsmee
@helloitsmee
June 2021
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factoriser: x² - x - 2
svp
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Thomas1106
x²-x-2 = 0
Δ = b²-4ac
Δ = (-1)²-4*1*(-2)
Δ = 1+8
Δ = 9
Δ > 0
x
₁ = (-b-√Δ)/2a = [-(-1)-√9]/2*1 = (1-3)/2 = -2/2 = -1
x₂ = (-b+√Δ)/2a = (1+3)/2 = 4/2 = 2
factorisation pour Δ > 0 :
a*(x-x₁)(x-x₂)
x²-x-2 = 1*(x+1)(x-2)
x²-x-2 = (x+1)(x-2)
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Helloitsmee
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Lista de comentários
Δ = b²-4ac
Δ = (-1)²-4*1*(-2)
Δ = 1+8
Δ = 9
Δ > 0
x₁ = (-b-√Δ)/2a = [-(-1)-√9]/2*1 = (1-3)/2 = -2/2 = -1
x₂ = (-b+√Δ)/2a = (1+3)/2 = 4/2 = 2
factorisation pour Δ > 0 : a*(x-x₁)(x-x₂)
x²-x-2 = 1*(x+1)(x-2)
x²-x-2 = (x+1)(x-2)