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csjardim
@csjardim
October 2020
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Fatore as expressões algébricas colocando o fator comum em evidência
12ab - 3b + a²b²
12m - 4p
9p²q - 12pq² - 3p - 5pq
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poty
Verified answer
12ab - 3b + a²b² = b(a²b+12a-3)
12m - 4p = 4(3m - p)
9p²q - 12pq² - 3p - 5pq = p(9pq-12q²-5q-3)
4 votes
Thanks 12
csjardim
Obrigada!
poty
Por nada,querida! Abraços!
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Verified answer
12ab - 3b + a²b² = b(a²b+12a-3)12m - 4p = 4(3m - p)
9p²q - 12pq² - 3p - 5pq = p(9pq-12q²-5q-3)