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camilaportela89
@camilaportela89
October 2020
2
10
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fatore os polinomios colocando o fator comum em evidencia de fração
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Heberwagner
ab + a²b - ab
8 4 2
a²b + ab - ab
4 8 2
a²b
+
ab - 4ab
4 8
a²b
- 3ab
4 8
ab(2a - 3)
8
ab(2a - 3)
4
3 votes
Thanks 1
3478elc
Verified answer
Ab/8 + a²b/4 - ab/2 => MMC(2, 4, 8) = 8
(ab + 2a²b - 4ab)/8 => (2a²b - 3ab)/8 =>
ab(2a - 3)/8
3 votes
Thanks 2
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Camilaportela89
April 2020 | 0 Respostas
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Lista de comentários
ab + a²b - ab
8 4 2
a²b + ab - ab
4 8 2
a²b + ab - 4ab
4 8
a²b - 3ab
4 8
ab(2a - 3)
8
ab(2a - 3)
4
Verified answer
Ab/8 + a²b/4 - ab/2 => MMC(2, 4, 8) = 8(ab + 2a²b - 4ab)/8 => (2a²b - 3ab)/8 => ab(2a - 3)/8