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Entirelyhuman
@Entirelyhuman
April 2019
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AIDEZ MOI, CETTE EXERCICE EST DIFFICILE. THÉORÈME DE THALES.
A appartient à [EF], B appartient à [EG] et (AB)//(FG).
( VOIR PHOTO )
Calculer les longueurs de EG et AB. Justifier les réponses.
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MathieuDC
/=divisé
EF/EA=EG/EB
donc
4,5+1,8/4,5=EG/5,5
donc
EG=((4,5+1,8)x5,5)/4,5
EG=7,7
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Lista de comentários
EF/EA=EG/EB
donc
4,5+1,8/4,5=EG/5,5
donc
EG=((4,5+1,8)x5,5)/4,5
EG=7,7