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Coeurdange12
@Coeurdange12
April 2019
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Sur un trajet de 1h30 Sergio a roulé pendant 25minutes a 75km/h, 50minutes a 85km/h et le reste a 95km/h
Quelle est sa visites se moyenne sur ce trajet? Elle sera arrondie au km/h
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Trajet en trois parties A, B et C
distance de la partie A
en 25 minutes a 75km/h
distance A = 75*25/60=
31.25 km
Distance partie B
en 50 minutes a 85km/h
distance B = 85*50/60 = 85*5/6 =
70.83 km
Distance partie C
le reste a 95km/h
temps du trajet C
1h30min-(25min+50min) = 1h30-1h15 = 15 min
en 15 min a 95 km/h
Distance C = 95*15/60 =
23.75 km
Distance totale du trajet
A+B+C = 31.25+70.83+23.75 =
125.83 km
En 1h30 soit 1.5 h il a parcouru 123.83 km
donc en 1h = 123.83/1.5 =83.886
soit
une vitesse moyenne de 84 km/h
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Verified answer
Trajet en trois parties A, B et Cdistance de la partie A
en 25 minutes a 75km/h
distance A = 75*25/60= 31.25 km
Distance partie B
en 50 minutes a 85km/h
distance B = 85*50/60 = 85*5/6 = 70.83 km
Distance partie C
le reste a 95km/h
temps du trajet C
1h30min-(25min+50min) = 1h30-1h15 = 15 min
en 15 min a 95 km/h
Distance C = 95*15/60 = 23.75 km
Distance totale du trajet
A+B+C = 31.25+70.83+23.75 = 125.83 km
En 1h30 soit 1.5 h il a parcouru 123.83 km
donc en 1h = 123.83/1.5 =83.886
soit une vitesse moyenne de 84 km/h