Articles
Register
Sign In
Search
Coeurdange12
@Coeurdange12
April 2019
1
26
Report
Sur un trajet de 1h30 Sergio a roulé pendant 25minutes a 75km/h, 50minutes a 85km/h et le reste a 95km/h
Quelle est sa visites se moyenne sur ce trajet? Elle sera arrondie au km/h
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
esefiha
Verified answer
Trajet en trois parties A, B et C
distance de la partie A
en 25 minutes a 75km/h
distance A = 75*25/60=
31.25 km
Distance partie B
en 50 minutes a 85km/h
distance B = 85*50/60 = 85*5/6 =
70.83 km
Distance partie C
le reste a 95km/h
temps du trajet C
1h30min-(25min+50min) = 1h30-1h15 = 15 min
en 15 min a 95 km/h
Distance C = 95*15/60 =
23.75 km
Distance totale du trajet
A+B+C = 31.25+70.83+23.75 =
125.83 km
En 1h30 soit 1.5 h il a parcouru 123.83 km
donc en 1h = 123.83/1.5 =83.886
soit
une vitesse moyenne de 84 km/h
1 votes
Thanks 4
More Questions From This User
See All
coeurdange12
June 2021 | 0 Respostas
Je n'arrive pas le C de l'exercice 1 et le A et C de l'exercice 2 pouvez vous m'aidez?
Responda
coeurdange12
January 2021 | 0 Respostas
Responda
Coeurdange12
May 2019 | 0 Respostas
Responda
Coeurdange12
May 2019 | 0 Respostas
Responda
Coeurdange12
April 2019 | 0 Respostas
Responda
Coeurdange12
April 2019 | 0 Respostas
Responda
×
Report "Sur un trajet de 1h30 Sergio a roulé pendant 25minutes a 75km/h, 50minutes a 85km/h et le reste a 95.... Pergunta de ideia de Coeurdange12"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Trajet en trois parties A, B et Cdistance de la partie A
en 25 minutes a 75km/h
distance A = 75*25/60= 31.25 km
Distance partie B
en 50 minutes a 85km/h
distance B = 85*50/60 = 85*5/6 = 70.83 km
Distance partie C
le reste a 95km/h
temps du trajet C
1h30min-(25min+50min) = 1h30-1h15 = 15 min
en 15 min a 95 km/h
Distance C = 95*15/60 = 23.75 km
Distance totale du trajet
A+B+C = 31.25+70.83+23.75 = 125.83 km
En 1h30 soit 1.5 h il a parcouru 123.83 km
donc en 1h = 123.83/1.5 =83.886
soit une vitesse moyenne de 84 km/h