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Playtutohd
@Playtutohd
April 2019
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HEEEEEELP 10 POINTS
EXERCICE 16 SEULEMENT
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Marilou62
G= (x-3) (x+1) = x² + x -3x -3 = x² -2x -3
a) l'image de 2 par g est : 2² - 2*2 - 3 = 4 - 4 - 3 = -3
b) l'image de -5 par g est : (-5)² - (-5)*2 - 3 = 25 + 10 - 3 = 32
c) antécédents de 0 par g : g = 0 ; x² - 2x - 3 = 0
Δ= b²-4ac = (-2)² - 4*1*(-3) = 4 + 12 = 16
x1= (-b-√Δ) / 2a = (2-√16) / 2*4 = -2 / 8 = -0.25
x2 = (-b+√Δ) / 2a = (2+√16) / 2*4 = 6/8 = 0.75
Les antécédents sont -0.25 et -0.75
d) g = -3 ; x² -2x - 3 = -3
x² - 2x - 3 + 3 = 0
x² - 2x = 0
x - 2 = 0
2 est un antécédent de -3 par g
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a) l'image de 2 par g est : 2² - 2*2 - 3 = 4 - 4 - 3 = -3
b) l'image de -5 par g est : (-5)² - (-5)*2 - 3 = 25 + 10 - 3 = 32
c) antécédents de 0 par g : g = 0 ; x² - 2x - 3 = 0
Δ= b²-4ac = (-2)² - 4*1*(-3) = 4 + 12 = 16
x1= (-b-√Δ) / 2a = (2-√16) / 2*4 = -2 / 8 = -0.25
x2 = (-b+√Δ) / 2a = (2+√16) / 2*4 = 6/8 = 0.75
Les antécédents sont -0.25 et -0.75
d) g = -3 ; x² -2x - 3 = -3
x² - 2x - 3 + 3 = 0
x² - 2x = 0
x - 2 = 0
2 est un antécédent de -3 par g