Articles
Register
Sign In
Search
Playtutohd
@Playtutohd
April 2019
1
65
Report
HEEEEEELP 10 POINTS
EXERCICE 16 SEULEMENT
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Marilou62
G= (x-3) (x+1) = x² + x -3x -3 = x² -2x -3
a) l'image de 2 par g est : 2² - 2*2 - 3 = 4 - 4 - 3 = -3
b) l'image de -5 par g est : (-5)² - (-5)*2 - 3 = 25 + 10 - 3 = 32
c) antécédents de 0 par g : g = 0 ; x² - 2x - 3 = 0
Δ= b²-4ac = (-2)² - 4*1*(-3) = 4 + 12 = 16
x1= (-b-√Δ) / 2a = (2-√16) / 2*4 = -2 / 8 = -0.25
x2 = (-b+√Δ) / 2a = (2+√16) / 2*4 = 6/8 = 0.75
Les antécédents sont -0.25 et -0.75
d) g = -3 ; x² -2x - 3 = -3
x² - 2x - 3 + 3 = 0
x² - 2x = 0
x - 2 = 0
2 est un antécédent de -3 par g
1 votes
Thanks 1
More Questions From This User
See All
playtutohd
June 2021 | 0 Respostas
Responda
playtutohd
June 2021 | 0 Respostas
Responda
playtutohd
June 2021 | 0 Respostas
Responda
playtutohd
June 2021 | 0 Respostas
Responda
Playtutohd
April 2019 | 0 Respostas
AIDEZZZZ moi svp 10 POINTS EXERCICE 15 SVP
Responda
Playtutohd
April 2019 | 0 Respostas
HELLLLLP 10 POINTS EXERCICE 13
Responda
Playtutohd
April 2019 | 0 Respostas
Responda
×
Report "HEEEEEELP 10 POINTS EXERCICE 16 SEULEMENT.... Pergunta de ideia de Playtutohd"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
a) l'image de 2 par g est : 2² - 2*2 - 3 = 4 - 4 - 3 = -3
b) l'image de -5 par g est : (-5)² - (-5)*2 - 3 = 25 + 10 - 3 = 32
c) antécédents de 0 par g : g = 0 ; x² - 2x - 3 = 0
Δ= b²-4ac = (-2)² - 4*1*(-3) = 4 + 12 = 16
x1= (-b-√Δ) / 2a = (2-√16) / 2*4 = -2 / 8 = -0.25
x2 = (-b+√Δ) / 2a = (2+√16) / 2*4 = 6/8 = 0.75
Les antécédents sont -0.25 et -0.75
d) g = -3 ; x² -2x - 3 = -3
x² - 2x - 3 + 3 = 0
x² - 2x = 0
x - 2 = 0
2 est un antécédent de -3 par g