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Yassmine68
@Yassmine68
June 2021
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HELP ME PLEASE, pour demain
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slyz007
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Notons x=DM
Alors MC=30-x
AireADM=AD*DM/2=12*x/2=6x
AireBCM=BC*MC/2=12*(30-x)/2=6(30-x)
On cherche x tel que 6x=1/3*6(30-x) soit :
6x=2(30-x)=60-2x
⇔8x=60
⇔x=7,5 cm
Il faut donc que
DM=7,5cm
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Verified answer
Notons x=DMAlors MC=30-x
AireADM=AD*DM/2=12*x/2=6x
AireBCM=BC*MC/2=12*(30-x)/2=6(30-x)
On cherche x tel que 6x=1/3*6(30-x) soit :
6x=2(30-x)=60-2x
⇔8x=60
⇔x=7,5 cm
Il faut donc que DM=7,5cm