bonsoir
2 x - 1 = x + 9
2 x - x = 9 + 1
x = 10
AB = AC pour x = 10
x + 9 = 3 x + 6
x - 3 x = 6 - 9
- 2 x = - 3
x = 3/2
AC = CB
3 x + 6 = 2 x - 1
3 x - 2 x = - 1 - 6
x = - 7
donc impossible
(x + 9 + 3 x + 6 + 2 x - 1 ) / 3
(6 x + 14 ) / 3
pas de possibilité
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bonsoir
2 x - 1 = x + 9
2 x - x = 9 + 1
x = 10
AB = AC pour x = 10
x + 9 = 3 x + 6
x - 3 x = 6 - 9
- 2 x = - 3
x = 3/2
AC = CB
3 x + 6 = 2 x - 1
3 x - 2 x = - 1 - 6
x = - 7
donc impossible
(x + 9 + 3 x + 6 + 2 x - 1 ) / 3
(6 x + 14 ) / 3
pas de possibilité