Articles
Register
Sign In
Search
benhamouyael03
@benhamouyael03
October 2020
1
67
Report
j aurais besoin d aide piur cet exercice de maths svp merciiiii
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
anaisevaristo
A) 3(a-1)=0
3a-3=0
3a=3
3a/3=3/3
a=1
b) a^2=0
a=0
c) a^2-3^2=0
a^2-9=0
a^2=9
a=-3 ou a=3
d) (x-3)^2=0
x-3=0
x=3
e) -3a=0
-3a/-3=0/-3
a=0
f) (a+3)(a-3)=0
a^2-9=0
a^2=9
a=-3 ou a=3
g) a(3a-1)=0
a=0 ou 3a-1=0
a=0 ou 3a=1
a=0 ou 3a/3=1/3
a=0 ou a=1/3
h) a^2=3
a= - racine carré de 3
ou
a= racine carré de 3
i) 3(a+1^2)=0
3(a+1)/3=0/3
a+1^2=0
a+1=0
a=-1
j) a/3=8/3
a=8
k) a/3=0
a/3x3=0x3
a=0
l) a/3=-4
a/3x3=-4x3
a=-12
Voilà je pense que c’est ça.
0 votes
Thanks 0
benhamouyael03
il faut que trouver un nombre qui vérifie l'égalité
More Questions From This User
See All
benhamouyael03
June 2021 | 0 Respostas
Responda
benhamouyael03
April 2021 | 0 Respostas
Responda
benhamouyael03
April 2021 | 0 Respostas
Responda
benhamouyael03
November 2020 | 0 Respostas
Responda
benhamouyael03
November 2020 | 0 Respostas
Responda
benhamouyael03
October 2020 | 0 Respostas
Responda
benhamouyael03
October 2020 | 0 Respostas
Responda
×
Report "j aurais besoin d aide piur cet exercice de maths svp merciiiii.... Pergunta de ideia de benhamouyael03"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
3a-3=0
3a=3
3a/3=3/3
a=1
b) a^2=0
a=0
c) a^2-3^2=0
a^2-9=0
a^2=9
a=-3 ou a=3
d) (x-3)^2=0
x-3=0
x=3
e) -3a=0
-3a/-3=0/-3
a=0
f) (a+3)(a-3)=0
a^2-9=0
a^2=9
a=-3 ou a=3
g) a(3a-1)=0
a=0 ou 3a-1=0
a=0 ou 3a=1
a=0 ou 3a/3=1/3
a=0 ou a=1/3
h) a^2=3
a= - racine carré de 3
ou
a= racine carré de 3
i) 3(a+1^2)=0
3(a+1)/3=0/3
a+1^2=0
a+1=0
a=-1
j) a/3=8/3
a=8
k) a/3=0
a/3x3=0x3
a=0
l) a/3=-4
a/3x3=-4x3
a=-12
Voilà je pense que c’est ça.