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Joanach
@Joanach
April 2019
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J'ai besoin d'aide pour l'exercice 2!
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PAU64
(3x - 5) (3x + 5) - (x - 6)²
= (3x)² - 5² - [x² - 2 * x * 6 + 6²]
= 9x² - 25 - (x² - 12x + 36)
= 9x² - 25 - x² + 12x - 36
= 8x² + 12x - 61
Les * désignent "fois".
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Têtedelinotte
s'il vous plait
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= (3x)² - 5² - [x² - 2 * x * 6 + 6²]
= 9x² - 25 - (x² - 12x + 36)
= 9x² - 25 - x² + 12x - 36
= 8x² + 12x - 61
Les * désignent "fois".