Réponse:
Exo 62 :
a)
[tex] \sqrt{ \frac{5}{16} } = \frac{ \sqrt{5} }{ \sqrt{16} } = \frac{1}{4} \sqrt{5} [/tex]
b)
[tex] \sqrt{ \frac{24}{2} } = \sqrt{12} = \sqrt{3 \times 4} = 2 \sqrt{ 3} [/tex]
c)
[tex] \frac{ \sqrt{2} }{ \sqrt{9} } = \frac{ \sqrt{2} }{ \sqrt{9} } = \frac{ \sqrt{2} }{3} = \frac{1}{3} \sqrt{2} [/tex]
d)
[tex] \frac{ \sqrt{15} }{ \sqrt{20} } = \sqrt{ \frac{15}{20} } = \sqrt{ \frac{3}{4} } = \frac{ \sqrt{3} }{ \sqrt{4} } = \frac{1}{2} \sqrt{3} [/tex]
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Réponse:
Exo 62 :
a)
[tex] \sqrt{ \frac{5}{16} } = \frac{ \sqrt{5} }{ \sqrt{16} } = \frac{1}{4} \sqrt{5} [/tex]
b)
[tex] \sqrt{ \frac{24}{2} } = \sqrt{12} = \sqrt{3 \times 4} = 2 \sqrt{ 3} [/tex]
c)
[tex] \frac{ \sqrt{2} }{ \sqrt{9} } = \frac{ \sqrt{2} }{ \sqrt{9} } = \frac{ \sqrt{2} }{3} = \frac{1}{3} \sqrt{2} [/tex]
d)
[tex] \frac{ \sqrt{15} }{ \sqrt{20} } = \sqrt{ \frac{15}{20} } = \sqrt{ \frac{3}{4} } = \frac{ \sqrt{3} }{ \sqrt{4} } = \frac{1}{2} \sqrt{3} [/tex]