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ThousandStars
@ThousandStars
April 2019
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J'ai besoin d'aide s'il vous plaît. Merci d'avance :)
Soit la fonction
f : x --> 4x + 1
Déterminer le signe de f(x) pour tout x.
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Bonjour
ThousandStars
f(x) = 4x + 1
1) f(x) ≤ 0 ⇔ 4x + 1 ≤ 0
f(x) ≤ 0 ⇔ 4x ≤ -1
f(x) ≤ 0 ⇔ x ≤ -1/4
2) f(x) ≥ 0 ⇔ 4x + 1 ≥ 0
f(x) ≥ 0 ⇔ 4x ≥ -1
f(x) ≥ 0 ⇔ x ≥ -1/4
Par conséquent,
si x ∈ ]-oo ; -1/4], alors f(x) ≤ 0
Si x ∈ [-1/4 ; +oo[, alors f(x) ≥ 0
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f(x) = 4x + 1
1) f(x) ≤ 0 ⇔ 4x + 1 ≤ 0
f(x) ≤ 0 ⇔ 4x ≤ -1
f(x) ≤ 0 ⇔ x ≤ -1/4
2) f(x) ≥ 0 ⇔ 4x + 1 ≥ 0
f(x) ≥ 0 ⇔ 4x ≥ -1
f(x) ≥ 0 ⇔ x ≥ -1/4
Par conséquent,
si x ∈ ]-oo ; -1/4], alors f(x) ≤ 0
Si x ∈ [-1/4 ; +oo[, alors f(x) ≥ 0