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SABINEMENDES
@SABINEMENDES
April 2019
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J'ai besoin de résoudre les équations suivantes
a) (x+7)²=9
b) (x-5)²=16
------
9
pouvez-vous m'expliquer comment le résoudre
merci
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geekkhalil
Salut :)
a) (x+7)²=9
(x+7)(x+7)=9
x × x + x × 7 + 7 × x + 7 × 7 = 9
x² + 14x + 49 = 9
x= - 10 ou x = - 4
b) (x-5)²=16
(x-5)(x-5)=16
x²-10 x+25 = 16
x= 1 ou x= 9
0 votes
Thanks 1
adami976
a) (x+7)²=9
(x +7)² - 9 = 0
(x +7)² - 9 =
(x +7)² - 3²
(x +7 -3)(x +7 +3) = (x - 4)(x+10)
(x - 4)(x+10) = 0
(x - 4) = 0 ou (x+10) = 0
x -4+4 = 0+4 x +10-10= 0-10
x = 4 x = -10
b) (x-5)²=16
(x -5)² -16 =0
(x -5)² -16 = (x -5 )² - 4²
(x-5+4)(x-5-4) = (x -1)(x -9
(
x -1)(x -1)(x -9) = 0
(x -1) =0 ou (x -1) = 0
x -1 +1= 0+1 x-1+1 = 0 +1
x = 1 x = 1
1 votes
Thanks 1
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a) (x+7)²=9
(x+7)(x+7)=9
x × x + x × 7 + 7 × x + 7 × 7 = 9
x² + 14x + 49 = 9
x= - 10 ou x = - 4
b) (x-5)²=16
(x-5)(x-5)=16
x²-10 x+25 = 16
x= 1 ou x= 9
(x +7)² - 9 = 0
(x +7)² - 9 = (x +7)² - 3²
(x +7 -3)(x +7 +3) = (x - 4)(x+10)
(x - 4)(x+10) = 0
(x - 4) = 0 ou (x+10) = 0
x -4+4 = 0+4 x +10-10= 0-10
x = 4 x = -10
b) (x-5)²=16
(x -5)² -16 =0
(x -5)² -16 = (x -5 )² - 4²
(x-5+4)(x-5-4) = (x -1)(x -9
(x -1)(x -1)(x -9) = 0
(x -1) =0 ou (x -1) = 0
x -1 +1= 0+1 x-1+1 = 0 +1
x = 1 x = 1