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Cassou123456
@Cassou123456
May 2019
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J'ai essayé mais j'ai réussit qui pourrait m'aider svp merci d'avance
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MonsieurFirdown
Verified answer
Bonjour
♤1. Pour x = 0 car 7×0 = 0
♤2. On a :
7×(x-3) = 0
7x - 21 = 0
7x = 21
x = 21/7 d'où x = 3
♤3. Que tout simplement a = 0 ou b = 0
♤4. On a : (x-8)(2x-1) = 0
●Un produit de facteur est nul si et seulement si au moins l'un des facteurs est nul on a donc :
x-8 = 0 <=> ou <=> 2x-1 = 0
x = 8 <=> ou <=> 2x = 1 d'où x = 1/2
S={1/2;2}
Voilà ^^
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Verified answer
Bonjour♤1. Pour x = 0 car 7×0 = 0
♤2. On a :
7×(x-3) = 0
7x - 21 = 0
7x = 21
x = 21/7 d'où x = 3
♤3. Que tout simplement a = 0 ou b = 0
♤4. On a : (x-8)(2x-1) = 0
●Un produit de facteur est nul si et seulement si au moins l'un des facteurs est nul on a donc :
x-8 = 0 <=> ou <=> 2x-1 = 0
x = 8 <=> ou <=> 2x = 1 d'où x = 1/2
S={1/2;2}
Voilà ^^