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Sanc77
@Sanc77
May 2019
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J'ai un problème à cette exercice 3, pouvez-vous m'aider ? Merci.
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loulakar
Verified answer
Bonsoir,
Nature du triangle CDE si a = 3 et b = 2 :
CE = a^2 + b^2
CE = 3^2 + 2^2
CE = 9 + 4
CE = 13
CD = 2ab
CD = 2 x 3 x 2
CD = 12
DE = a^2 - b^2
DE = 3^2 - 2^2
DE = 9 - 4
DE = 5
On utilise la réciproque du théorème de pythagore :
CE^2 = 13^2
CE^2 = 169
CD^2 + DE^2 = 12^2 + 5^2
CD^2 + DE^2 = 144 + 25
CD^2 + DE^2 = 169
CE^2 = CD^2 + DE^2
Le triangle CDE est donc rectangle
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Verified answer
Bonsoir,Nature du triangle CDE si a = 3 et b = 2 :
CE = a^2 + b^2
CE = 3^2 + 2^2
CE = 9 + 4
CE = 13
CD = 2ab
CD = 2 x 3 x 2
CD = 12
DE = a^2 - b^2
DE = 3^2 - 2^2
DE = 9 - 4
DE = 5
On utilise la réciproque du théorème de pythagore :
CE^2 = 13^2
CE^2 = 169
CD^2 + DE^2 = 12^2 + 5^2
CD^2 + DE^2 = 144 + 25
CD^2 + DE^2 = 169
CE^2 = CD^2 + DE^2
Le triangle CDE est donc rectangle