J'ai un triangle rectangle FCB en B : BC = 10.8, CF = 21 cm et BF = x ...
Comment trouver 'x' ?
Vue que CF = Côté de l'hopoténuse ??
BF² + CF²-BC²
BF² = 21² - 10.8² = 441 - 116.6 = 324.4
BF² = racine de 324.4 = 18.01
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BF² + CF²-BC²
BF² = 21² - 10.8² = 441 - 116.6 = 324.4
BF² = racine de 324.4 = 18.01