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Harpetdu61
@Harpetdu61
April 2019
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J'ai vraiment besoin d'aide pour mon exercice en échange je vous offres des points ...
merci a ceux qui m'aideront :merci merci...
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slyz007
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2a) TanFEG=FG/FE=a/a=1
2b) FEG=45° (car dans un carré la diagonale est bissectrice) donc tan45°=1
3a) Par Pythgore : EG²=EF²+FG²=a²+a²=2a²
Donc EG=a√2
3b) Cos45=CosFEG=EF/EG=a/(a√2)=1/√2=√2/2
3b) Tan45=Sin45/cos45=1 donc sin45=cos45
Sin45°=√2/2
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Lista de comentários
Verified answer
2a) TanFEG=FG/FE=a/a=12b) FEG=45° (car dans un carré la diagonale est bissectrice) donc tan45°=1
3a) Par Pythgore : EG²=EF²+FG²=a²+a²=2a²
Donc EG=a√2
3b) Cos45=CosFEG=EF/EG=a/(a√2)=1/√2=√2/2
3b) Tan45=Sin45/cos45=1 donc sin45=cos45
Sin45°=√2/2