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Kawol37
@Kawol37
April 2019
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Je developpe et je réduis C
C=(x-1)(2x+5)+(x-1)^2
J'ai trouvé
C=3x^2-x-4
Pour la factorisation, j'ai trouvé
C=(x-1)(x+6)
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Commentaires
forme factorisée
C=(x-1)(2x+5)+(x-1)^2
=(x-1)(2x+5+x-1)
=(x-1)(3x+4)
forme développée
C=(x-1)(3x+4)
=3x²-3x+4x-4
=3x²+x-4
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Commentaires
Développement:
C= (x-1)(2x+5)+(x-1)
²
C= 2x² + 5x - 2x - 5 + x² - 2x + 1
C= 3x² + x - 4
Ta réponse est donc juste.
Factorisation:
C= (x-1)(2x+5)+(x-1)
²
C= (x-1) (2x + 5 + x -1)
C= (x-1) (3x+4)
Ta réponse est fausse.
J'espère t'avoir aidé(e) ! :)
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C=(x-1)(2x+5)+(x-1)^2
=(x-1)(2x+5+x-1)
=(x-1)(3x+4)
forme développée
C=(x-1)(3x+4)
=3x²-3x+4x-4
=3x²+x-4
C= (x-1)(2x+5)+(x-1)²
C= 2x² + 5x - 2x - 5 + x² - 2x + 1
C= 3x² + x - 4
Ta réponse est donc juste.
Factorisation:
C= (x-1)(2x+5)+(x-1)²
C= (x-1) (2x + 5 + x -1)
C= (x-1) (3x+4)
Ta réponse est fausse.
J'espère t'avoir aidé(e) ! :)