Articles
Register
Sign In
Search
Leahharold62800
@Leahharold62800
January 2021
1
50
Report
je n'y arrive pas a mon dm aidez moi svp
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
aymanemaysae
Bonjour ;
1)
En considérant le triangle HZA rectangle en H , on a :
sin(HZA) = HA/HZ = 16,5/24 = 0,6875 ;
donc : HZA ≈ 43,43° .
En considérant le triangle HZB rectangle en H , on a :
sin(HZB) = HB/HZ = (HA + AB)/HZ = (16,5 + 7,3)/24 ≈ 0,9917 ;
donc : HZB ≈ 82,60° .
b)
L'angle AZB = HZB - HZA ≈ 82,60° - 43,43° = 39,17° .
0 votes
Thanks 1
Leahharold62800
merci mais lexercice 2 ?
More Questions From This User
See All
Leahharold62800
January 2021 | 0 Respostas
Rebonjour pouvez vous maidez a l'exercice 2 svp
Responda
Leahharold62800
May 2019 | 0 Respostas
Responda
Leahharold62800
May 2019 | 0 Respostas
Responda
×
Report "je n'y arrive pas a mon dm aidez moi svp.... Pergunta de ideia de Leahharold62800"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
1)
En considérant le triangle HZA rectangle en H , on a :
sin(HZA) = HA/HZ = 16,5/24 = 0,6875 ;
donc : HZA ≈ 43,43° .
En considérant le triangle HZB rectangle en H , on a :
sin(HZB) = HB/HZ = (HA + AB)/HZ = (16,5 + 7,3)/24 ≈ 0,9917 ;
donc : HZB ≈ 82,60° .
b)
L'angle AZB = HZB - HZA ≈ 82,60° - 43,43° = 39,17° .