x = 6
[tex]{\sf{\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX }}[/tex]
[tex]\qquad\boxed{ \begin{array}{l}\qquad\sf\large 3(x+3) -5 = 22 \qquad \qquad \\ \\ \qquad \sf\large 3x +9-5=22 \\ \\ \qquad \large \sf 3x = 22-9+5 \\ \\ \qquad \sf \large 3x = 13+5 \\ \\ \qquad \large \sf 3x=18 \\ \\ \qquad \sf \large x = \frac{18}{3} \\ \\ \sf \large \boxed{ \quad\colorbox{gold}{ }\boxed{\sf x =6} \quad} \end{array}} [/tex]
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x = 6
[tex]{\sf{\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX\Huge \_ \tiny \LaTeX \Huge \_ \tiny \LaTeX }}[/tex]
[tex]\qquad\boxed{ \begin{array}{l}\qquad\sf\large 3(x+3) -5 = 22 \qquad \qquad \\ \\ \qquad \sf\large 3x +9-5=22 \\ \\ \qquad \large \sf 3x = 22-9+5 \\ \\ \qquad \sf \large 3x = 13+5 \\ \\ \qquad \large \sf 3x=18 \\ \\ \qquad \sf \large x = \frac{18}{3} \\ \\ \sf \large \boxed{ \quad\colorbox{gold}{ }\boxed{\sf x =6} \quad} \end{array}} [/tex]
3 ( × + 3 ) - 5= 22
3 × + 9 - 5= 22
3 × = 22 - 9 + 5
3 × = 13 + 5
3 × = 18
× = 18/3
x = 6
Então a resposta correta é x = 6
Espero ter ajudado