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Mae62
@Mae62
May 2019
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L'équation : 6y au carré+11y-7=7y+7 a pour solution...?
aidez moi svp je n'y arrive pas.
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nadiab
Bonjour,
6y²+11y-7=7y+7
6y²+11y-7-7y-7=0
6y²+4y=0
y(6y+4)=0
y=0
ou
6y+4=0
y= -4/6=-2/3
Donc solutions= {-2/3;0}
1 votes
Thanks 1
More Questions From This User
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mae62
January 2021 | 0 Respostas
Bonjour pouvez vous m'aidez svp
Responda
Mae62
May 2019 | 0 Respostas
Bonjour, pouvez vous m'aidez svp
Responda
Mae62
May 2019 | 0 Respostas
Bonjour, pouvez vous m'aidez svp
Responda
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6y²+11y-7=7y+7
6y²+11y-7-7y-7=0
6y²+4y=0
y(6y+4)=0
y=0
ou
6y+4=0
y= -4/6=-2/3
Donc solutions= {-2/3;0}