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Cameron60
@Cameron60
June 2021
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L'exo 11 et 14 svp merci d'avance :)
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Salut
Exercice 11
a. La composition du noyau est :
A = 28 : le nombre de nucléons
Z = 14 : le nombre de protons
A = Z+N
N = A-Z
N = 28-14
N = 14 : le nombre de neutrons
b. La masse de son noyau est :
m = A×mn
m = 28×1,7×10⁻²⁷
m = 47,6×10⁻²⁷ kg
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Verified answer
SalutExercice 11
a. La composition du noyau est :
A = 28 : le nombre de nucléons
Z = 14 : le nombre de protons
A = Z+N
N = A-Z
N = 28-14
N = 14 : le nombre de neutrons
b. La masse de son noyau est :
m = A×mn
m = 28×1,7×10⁻²⁷
m = 47,6×10⁻²⁷ kg