Articles
Register
Sign In
Search
Zarate11
@Zarate11
April 2019
2
70
Report
L'expression factorisée de x² -16
A=n'existe pas ?
B=(x-4)(x+4)?
C=(x-4)²?
Justifier. merci pour l'aide !
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
nonotata
Identitie remarquable
(a-b)(a+b) = a² -b²
donc la bonne response est la b
il te suffit de la developper
(x-4)(x+4)
= x² +4x-4x-16
= x²-16
0 votes
Thanks 1
nathalienouts
Identité remarquable a²-b² = (a+b)(a-b)
B est la solution
(x-4)(x+4)
= x²+4x-4x-16
= x²-16
0 votes
Thanks 1
More Questions From This User
See All
Zarate11
April 2019 | 0 Respostas
Qui peut m'aider svp c'est mon dm pour demain sans l'exo 4 .
Responda
Zarate11
April 2019 | 0 Respostas
Peut-on associer x-2 ? Et en faire 2x ?
Responda
Zarate11
April 2019 | 0 Respostas
Responda
×
Report "L'expression factorisée de x² -16 A=n'existe pas ? B=(x-4)(x+4)? C=(x-4)²? Justifier. merci pour l'.... Pergunta de ideia de Zarate11"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
(a-b)(a+b) = a² -b²
donc la bonne response est la b
il te suffit de la developper
(x-4)(x+4)
= x² +4x-4x-16
= x²-16
B est la solution
(x-4)(x+4)
= x²+4x-4x-16
= x²-16