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Kenzadu67
@Kenzadu67
May 2019
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Pouvez vous me résoudre ses inéquations svp ? Merci : 2x+3<5
4x-1>7 , 2x+1 /<2
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nkar
Verified answer
Salut;
2x+3 < 5
2x +3 -3 < 5 -3
2x < 2
x < 2/2
x < 1
4x-1 > 7
4x -1 +1 > 7 +1
4x > 8
x > 8/4
x > 2
2x +1 ≤ 2
2x +1 -1 ≤ 2 -1
2x ≤ 1
x ≤ 1/2
Cordialement.
2 votes
Thanks 1
kenzadu67
Merci bcp
nkar
De rien
kenzadu67
Et -x_>3
nkar
-x >= 3 ---> -x * (-1) =< 3 * (-1) ---> x =< -3
kenzadu67
Merci énormément !
winner123
Bonsoir
2 x + 3 < 5
2 x < 5 - 3
2 x < 2
x < 1
4 x - 1 > 7
4 x > 7 + 1
4 x > 8
x > 2
2 x + 1 < 2
2 x < 2 - 1
2 x < 1
x < 1/2
1 votes
Thanks 1
kenzadu67
Merci
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Lista de comentários
Verified answer
Salut;2x+3 < 5
2x +3 -3 < 5 -3
2x < 2
x < 2/2
x < 1
4x-1 > 7
4x -1 +1 > 7 +1
4x > 8
x > 8/4
x > 2
2x +1 ≤ 2
2x +1 -1 ≤ 2 -1
2x ≤ 1
x ≤ 1/2
Cordialement.
2 x + 3 < 5
2 x < 5 - 3
2 x < 2
x < 1
4 x - 1 > 7
4 x > 7 + 1
4 x > 8
x > 2
2 x + 1 < 2
2 x < 2 - 1
2 x < 1
x < 1/2