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Annasz
@Annasz
May 2019
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Maths niveaux 4ème Bonjour je ne comprends rien à l’exercice 2 si quelqu’un pouvait m’aider svp
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inequation
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Bonjour,
1) Volume de la pyramide SABCD:
V= (A x h) / 3
V= (30² x 18) / 3
V= 5 400 cm³.
2) Le volume de la pyramide SEFGH:
Le coefficient de réduction k:
k= SO'/ SO= 6/18= 0.333
Donc
V'= k³ V
V'= (0.333)³ x 5 400
V'= 199.4 cm³.
3) Calcul du volume de la partie inferieur:
V= 5 400 - 199.4
V= 5 200.6 cm³.
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cossin23
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Bonjour,tu as la réponse
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Thanks 1
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Verified answer
Bonjour,1) Volume de la pyramide SABCD:
V= (A x h) / 3
V= (30² x 18) / 3
V= 5 400 cm³.
2) Le volume de la pyramide SEFGH:
Le coefficient de réduction k:
k= SO'/ SO= 6/18= 0.333
Donc
V'= k³ V
V'= (0.333)³ x 5 400
V'= 199.4 cm³.
3) Calcul du volume de la partie inferieur:
V= 5 400 - 199.4
V= 5 200.6 cm³.
Verified answer
Bonjour,tu as la réponse