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tera
@tera
October 2020
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Me ajude na atividade de matrizes.Desenvolva: sen(2pi+x) e cos(pi-x)
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Lucaslopes1
---> sen(a+b) = sen(a).cos(b) + sen(b).cos(a) e sen(a-b) = sen(a).cos(b) - sen(b).cos(a)
---> cos(a+b) = cos(a).cos(b) - sen(a).sen(b) e cos(a-b) = cos(a).cos(b) + sen(a).sen(b)
---> seno 2π = 0, cosseno 2π = 1
sen(2π+x) = sen(2π).cos(x) + sen(x).cos(2π)
sen(2π+x) = (0).cos(x) + sen(x).(1)
sen(2π+x) = sen(x)
cos(2π-x) = cos(2π).cos(x) + sen(2π).sen(x)
cos(2π-x) = (1).cos(x) + (0).sen(x)
cos(2π-x) = cos(x)
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---> cos(a+b) = cos(a).cos(b) - sen(a).sen(b) e cos(a-b) = cos(a).cos(b) + sen(a).sen(b)
---> seno 2π = 0, cosseno 2π = 1
sen(2π+x) = sen(2π).cos(x) + sen(x).cos(2π)
sen(2π+x) = (0).cos(x) + sen(x).(1)
sen(2π+x) = sen(x)
cos(2π-x) = cos(2π).cos(x) + sen(2π).sen(x)
cos(2π-x) = (1).cos(x) + (0).sen(x)
cos(2π-x) = cos(x)