me ajudem 1) calcule sec 105 grau.... Pergunta de ideia dejuninho1234

March 2022 1 52 Report

me ajudem
1) calcule
sec 105 grau

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Veja que 105° = 60° + 45°

$cos105^o=cos(60^o+45^o)=cos60^o.cos45^o-sen60^o.sen45^o\\
\\
cos105^o=\frac{1}{2}.\frac{\sqrt2}{2}-\frac{\sqrt3}{2}.\frac{\sqrt2}{2}=\frac{\sqrt2}{4}-\frac{\sqrt{6}}{4}=\frac{\sqrt2-\sqrt6}{4}\\
\\
sec105^o=\frac{1}{cos105^o}=\frac{4}{\sqrt2-\sqrt6}=-\sqrt2-\sqrt6$

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SOCORROME AJUDEM POR FAVOR1) CALCULE: A) SECANTE 105 GRAUS

SOCORRO P AMANHA1) Calcule:A) COS 165

o que significa considir?????????

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