Verified answer

Explicação passo a passo:

3)

[tex]X +\left[\begin{array}{ccc}5&3\\2&1\\\end{array}\right] = \left[\begin{array}{ccc}8&2\\6&4\\\end{array}\right] = >[/tex]

[tex]X = \left[\begin{array}{ccc}8&2\\6&4\\\end{array}\right] - \left[\begin{array}{ccc}5&3\\2&1\\\end{array}\right] = >[/tex]

[tex]X =\left[\begin{array}{ccc}8-5&2-3\\6-2&4-1\\\end{array}\right] = >[/tex]

[tex]X = \left[\begin{array}{ccc}3&-1\\4&3\\\end{array}\right][/tex]

4)

[tex]M =\left[\begin{array}{ccc}8&-6&2\\10&-4&4\\\end{array}\right][/tex]

a)

[tex]2M =\left[\begin{array}{ccc}8*2&-6*2&2*2\\10*2&-4*2&4*2\\\end{array}\right] = >[/tex]

[tex]2M =\left[\begin{array}{ccc}16&-12&4\\20&-8&8\\\end{array}\right][/tex]

b)

[tex]\frac{M}{2} =\left[\begin{array}{ccc}\frac{8}{2}&\frac{-6}{2}&\frac{2}{2}\\\frac{10}{2}&\frac{-4}{2}&\frac{4}{2}\\\end{array}\right] = >[/tex]

[tex]\frac{M}{2} =\left[\begin{array}{ccc}4&-3&1\\5&-2&2\\\end{array}\right][/tex]