Bonjour,

Réponse :

[tex]\sf A = 5 \times \dfrac{2}{3}-\dfrac{1}{3}[/tex]

[tex]\sf A = \dfrac{10}{3}-\dfrac{1}{3}[/tex]

[tex]\sf A = \dfrac{9}{3}[/tex]

[tex]\red{\boxed{\sf A=3}}[/tex]

[tex]\\[/tex]

[tex]\sf B = \dfrac{7}{4} -\dfrac{3}{4}\times \dfrac{3}{2}[/tex]

[tex]\sf B = \dfrac{7\times \blue{2}}{4\times \blue{2}} -\dfrac{3 \times 3}{4 \times 2}[/tex]

[tex]\sf B = \dfrac{14}{8} -\dfrac{9}{8}[/tex]

[tex]\red{\boxed{\sf B = \dfrac{5}{8} }}[/tex]

[tex]\\[/tex]

[tex]\sf C = \left(\dfrac{5}{6} + \dfrac{7}{12} \right) \times \dfrac{3}{5}[/tex]

[tex]\sf C = \left(\dfrac{5 \times \blue{2}}{6 \times \blue{2} } + \dfrac{7}{12} \right) \times \dfrac{3}{5}[/tex]

[tex]\sf C = \left(\dfrac{10}{12} + \dfrac{7}{12} \right) \times \dfrac{3}{5}[/tex]

[tex]\sf C = \dfrac{10+7}{4 \times \orange{3}} \times \dfrac{\orange{3}}{5}[/tex]

[tex]\sf C = \dfrac{17}{4} \times \dfrac{1}{5}[/tex]

[tex]\red{\boxed{\sf C = \dfrac{17}{20}}}[/tex]

[tex]\\[/tex]

[tex]\\[/tex]

En espérant t'avoir aidé, bonne continuation ! ☺️