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perrinecbs34
@perrinecbs34
July 2022
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merci de démontrer
a^2 est pair ou impair
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astriddddd25
Bonjour, Si a est pair → a² = (2k)² = 4k² = 2(2k²) donc pairSi a est impair → a² = (2k+1)² = 4k² + 4k + 1 = 2(2k² + 2k) + 1 donc impairConclusion a² est pair ou impair
2 votes
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Skabetix
pourquoi a = k+1 ?
astriddddd25
un nombre quelconque k si on lui ajoute 1
soit k est pair alors il est impair soit l’inverse c’est général
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soit k est pair alors il est impair soit l’inverse c’est général