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Rosa1
@Rosa1
April 2019
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Montrer que x-1est diviseur de x²+4x+1
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overjay
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Si c'est vrai alors
x²+4x+1 = (x-1) . (ax+b) = ax² + x.(b-a) - b
d'où
a= 1
b-a = 4
b = - 1
ce qui est impossible.
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Verified answer
Si c'est vrai alorsx²+4x+1 = (x-1) . (ax+b) = ax² + x.(b-a) - b
d'où
a= 1
b-a = 4
b = - 1
ce qui est impossible.