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karlagui
@karlagui
July 2022
1
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o resto da divisão do polinômio g(k)=4k3=12k2+k-4 por 2k+3 e:
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3478elc
Verified answer
g(k)=4k3+12k2+k-4 por 2k+3 e: raiz : 2k + 3 = 0
2k = - 3
k = - 3/2
R= 4(
-3
)^3+12(
-3
)^2 + (
-3
) - 4
2 2 2
R= -4(
27
) + 12(
9
) -
3
- 4
8 4 2
R= -
27
+ 3( 9) -
3
- 4
2 2
R= -
27
+ 27 -
3
- 4
2 2
R=
- 27 + 54 - 3 - 8
2
R=
16
===> R = 8
2
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Verified answer
g(k)=4k3+12k2+k-4 por 2k+3 e: raiz : 2k + 3 = 0
2k = - 3
k = - 3/2
R= 4(-3)^3+12(-3)^2 + (-3) - 4
2 2 2
R= -4(27) + 12( 9) - 3 - 4
8 4 2
R= - 27 + 3( 9) - 3 - 4
2 2
R= - 27 + 27 - 3 - 4
2 2
R= - 27 + 54 - 3 - 8
2
R= 16 ===> R = 8
2